A light rope is wound around a hollow cylinder of mass 5 kg and radius 70 cm. The rope is pulled with a force of 52.5 N. The angular acceleration of the cylinder will be_____rad s -2 .
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(15)
The formula to calculate the moment of inertia (I) of the cylinder about its radial axis is given by
I = Mr 2 ...
Also, the torque (r) on the cylinder about the central axis because of the application of the external force is given by
= Fr ...
Also, the torque can be expressed as
= I
...
Substitute the expressions from equation and into equation and simplify to obtain the angular acceleration.
Fr= Mr 2 
...
Substitute the values of the known parameters into equation to calculate the required angular acceleration. a = 52 - 5N

= 15 rad s -2
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems